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Botou Chenxin Machinery Equipment Manufacturing Co., Ltd
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Botou Chenxin Machinery Equipment Manufacturing Co., Ltd
The internal pressure corrugated compensator is mainly used to compensate for axial displacement, and can also compensate for lateral displacement ..
NegotiableUpdate on 03/14
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Overview
Axial type internal pressure corrugated compensator is mainly used to compensate for axial displacement, and can also compensate for lateral displacement or axial and lateral composite displacement. It has the ability to compensate for angular displacement, but it is generally not used to compensate for angular displacement
Product Details
Axial type internal pressure corrugated compensator
Axial type internal pressure corrugated compensator is mainly used to compensate for axial displacement, and can also compensate for lateral displacement or axial and lateral composite displacement. It has the ability to compensate for angular displacement, but it is generally not used to compensate for angular displacement.
model:
Our company produces DN32-DN8000 with pressure levels ranging from 0.1Mpa to 2.5Mpa
Connection method:
1. Flange connection 2, connecting pipe connection
Product axial compensation amount:
18mm-400mm
instructions:
The internal pressure corrugated compensator is mainly used to compensate for axial displacement, as well as lateral displacement or the combined displacement of axial and lateral directions. It has the ability to compensate for angular displacement, but it is generally not used to compensate for angular displacement.
Calculation of the force exerted on the support by the internal pressure corrugated compensator:
Internal pressure thrust: F=100 · P · A Axial elasticity: Fx=Kx · (f · X)
Lateral elasticity: Fy=Ky · Y Bending moment: My=Fy · L
Bending moment: M θ=K θ ·θ Composite bending moment: M=My+M θ
In the formula: Kx: axial stiffness N/mm X: actual axial displacement mm
Ky: Lateral stiffness N/mm Y: Actual lateral displacement mm
K θ: angular stiffness N · m/degree θ: actual displacement measurement in the angular direction
P: Working pressure MPa A: effective area of corrugated pipe cm2 (check sample)
L: Distance m from the midpoint of the compensator to the support
4、 Application example:
A certain carbon steel pipeline with a nominal diameter of 500mm, a working pressure of 0.6MPa, a medium temperature of 300 ° C, and an ambient minimum temperature of -10 ° C. The installation temperature of the compensator is 20 ° C. According to the pipeline layout (as shown in the figure), an internal pressure corrugated compensator needs to be installed to compensate for axial displacement X=32mm, lateral displacement Y=2.8mm, and angular displacement θ=1.8 degrees. Given L=4m, the number of fatigue failures of the compensator is considered to be 15000 times, and the force on support A is calculated.
Solution: (1) According to the axial displacement of the pipeline X=32mm.
Y=2.8mm。
θ=1.8 degrees.
According to the sample, the axial displacement X0 of 0.6TNY500 × 6F is 84mm,
Lateral displacement: Y0=14.4mm. Angular displacement: θ 0=± 8 degrees.
Axial stiffness: Kx=282N/mm. Lateral stiffness: Ky=1528N/mm.
Angular stiffness: K θ=197N · m/degree. Use the following relationship to determine whether this compensator meets the requirements of the problem:
Substitute the above parameters into the equation:
(2) The pre deformation amount △ X for the compensator is:
(2) The pre deformation amount △ X for the compensator is:
Due to the positive value of △ X, a "pre stretching" of 13mm is required before leaving the factory.
(3) Calculation of stress on support A:
Internal pressure thrust: F=100 · P · A=100 × 0.6 × 2445=14600 (N)
Axial elasticity: Fx=Kx · (f · X)=282 × (1/2 × 32)=4512 (N)
Lateral elasticity: Fy=Ky · Y=1528 × 2.8=4278.4 (N)
Bending moment: My=Fy · L=4278.4 × 4=17113.6 (N · m)
Mθ=Kθ·θ =197×1.8=354.6(N·m)
Composite bending moment: M=My+M θ=17113.6+354.6=17468.2 (N · m)
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